Sunday, December 2, 2018

Ion product of water


The Ion product of water:
In the study of acid-base reactions, the hydrogen ion concentration is key; its value indicates the acidity or basicity of the solution. Because only a very small fraction of water molecules are ionized, the concentration of water, [H2O], remains virtually unchanged (concentration of pure water, [H2O] = 55.5M). Therefore, the equilibrium constant for the auto-ionization of water, according to Equation is:
Because we use H+(aq) and H3O+(aq) interchangeably to represent the hydrated proton, the equilibrium constant can also be expressed as:

                                                          
To indicate that the equilibrium constant refers to the auto-ionization of water, we replace Kc by Kw:

                                              
Where Kw is called the ion-product constant, which is the product of the molar concentrations of H+ and OH- ions at a particular temperature:
In pure water at 25°C, the concentrations of H+ and OH- ions are equal and found to be [H+] =1.0x1027 M and [OH]= 1.0x1027M. Thus, at 25°C:



Whether we have pure water or an aqueous solution of dissolved species, the following relation always holds at 25°C:
Whenever [H+]=[OH-], the aqueous solution is said to be neutral. In an acidic solution there is an excess of H+ ions and [H+]>[OH-]. In a basic solution there is an excess of hydroxide ions, so [H+]<[OH-]. In practice we can change the concentration of either H+ or OH- ions in solution, but we cannot vary both of them independently. If we adjust the solution so that [H+]=1.0x10-6 M, the OH- concentration must change to:







No comments:

Post a Comment